Expand and simplify
a. 2(x+y)+3(x+y)
b. 5(x+y)+2(5x-y)
c. 5(x+y)+3(2x-y)
d. 3(2c+d)-2(4p-3)
e. 4(2p+2q)-3(2p-q)

intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

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it has the same slope and a different y-intercept

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