Can you me with my question! i'm desperate! it's due for monday: is it possible to remove ten unit cubes from a 3 by 3 by 3 cube made from 27 unit cubes so that the surface area of the remaining solid is the same as the surface area of the original 3 by 3 by 3 cube? in how many different ways can this be done?you! i'd really appreciate if you could ! xx

I observed that if I remove one (or all 8) piece(s) in the corners, and only them without adjacent ones, the total area does not change.

I consider the surface area of a small square as a unit of surface.

I removed all eight corners, leaving the total area unchanged.

I removed the central cube of the top surface obtaining an increase of the surface area with four units.

I removed one cube from the middle of an edge at the top (any of the four remaining) and I arrived at a figure with ten cubes less then the original one but with the same surface area.

7! = 7×6×5×4×3×2

3! = 3× 2

as 7! is multiple of 3! because 7! contains 3! that is 3× 2 as factor

so 7! /(3! ) = 7× 6× 5× 4

= 42 × 20

= 840

its b) 840✌✌✌

dhruv⭐

i can't solve unless i know what the line is

step-by-step explanation:

welcome to/p>