What is the equation of a line with a slope of -1/2 and passes through the point (6,-6)

Y = mx + b
slope(m) = -1/2
(6,-6)x = 6 and y = -6
now we sub into the formula and find b, the y int
-6 = -1/2(6) + b
-6 = - 3 + b
-6 + 3 = b
-3 = b

so ur equation is : y = -1/2x - 3 <==