Acity’s bus line is used more as the urban population density increases. the more people in an area, the more likely bus lines will be utilized. the population of belmont, ma, is 24,729 and covers an area of 4.66 mi2. the population of easton, ma, is 23,112 and covers an area of 28.4 mi2. which city’s residents are more likely to use public buses? explain. the residents of belmont are more likely to use public transportation because the city has the highest population density. the residents of easton are more likely to use public transportation because the city has the highest population density. the residents of both cities will not use the bus line because the population density is too high. the residents of both cities are equally likely to use public transportation because the population densities are equal.

Answer with explanation:

it is given that city's bus line is used more as the urban population density increases.

Population density is defined as ,total population per unit Area.

→Population Density of Belmont

In 1 Square mile,of Belmont approximately  5307 people Resides.

→Population Density of Easton

In 1 Square mile,of Easton Approximately 813 people Resides.

From Above two,we conclude that

→Population Density of Belmont > Population Density of Easton

Option A: The residents of Belmont are more likely to use public transportation because the city has the highest population density.

c. y = 1/4 x + 5

step-by-step explanation:

first, put the equation of the line on the graph into slope-intercept form

(y = mx + b):   y = -4x + 8

second, a perpendicular line has to have "an opposite/reciprocal slope" to the original slope. so, find the "m" value in your original equation (it's -4, right? )

original slope: m = -4   perpendicular slope: change the sign to its opposite and find the reciprocal ("flip" the number)

new slope is now positive (b/c the original slope was negative 4), and it's 1/4 (not the original slope of 4 or 4/1)