Using only a compass and a straightedge you are constructing a line perpendicular to ab and passing through a given point m on ab with a compass of set width you have drawn arcs that intersect ab on each side of m and marked the two intersection points as p and q the next step in this construction is to place the compass needle on

P (or Q) and draw an arc in the approximate location of the reflection of M across AB.

Step-by-step explanation:

Arcs drawn from P and Q in the approximate location of the reflection of M across AB will intersect at that point of reflection (M'). The line joining M and M' will be perpendicular to AB and through point M, as desired.

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step-by-step explanation:

x^(1/6) · x^(1/6) · x^(1/6)   ·x^(1/6) = x^(4/6)   since we add the exponents

4/6 can be simplified to 2/3

the simplified form is x^(2/3)

a .4y4

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