In δjkl, solve for x. triangle jkl where angle k is a right angle. kl measures 34. jl measures x. angle l measures 27 degrees. 74.89 30.29 38.16 66.73

The value of x in ΔJKL is 38.16

In the attached photo,

Angle θ = 27°

Adjacent = 34

We can obtain the value of x by using the cosine ratio as illustrated below:

Cos θ = Adjacent / Hypothenus

Cos 27 = 34 / x

Cross multiply

xCos 27 = 34

Divide both side by Cos 27

x = 34 / Cos 34

Therefore, the value of x is 38.16

Learn more about trig ratios on: link

10.4 inches

step-by-step explanation:

2x2x2.6

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