7y + 4x = 3; (-4, -7) write the equation in slope intercept form of the line that is perpendicular to the graph of the equation and passes through the given point.

Step-by-step explanation:

we have the original line equation

clearing for y:

Now we have an equation of the form slope- intercept:

where m is the slope and b is the y-intercept.

thus, the slope of the original line is:

Now to find the new line, since it has to be perpendicular their slopes must satisfy the following:

where m is the slope of the original line, and m1 is the slope of the new line:

this is the slope of the new perpendicular line that passes trough the point (-4,-7), so now we use the point slope equation to find the equation of said line:

where we know , and from the point (-4,-7)

so we have:

and we clear for y to leave the equation in the slope intercept form:

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step-by-step explanation:

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the answer to this would be 5x^3-6x^2-24 over 3x^2

hope this if needed hmu