Mathematics, 20.07.2019 11:20 Frenchfries13

Acompany will need 40,000 in 6 years for a new addition. to meet the goal, the company deposits money into an account today that pays 4% annual intrest compund quarterly.

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"A company will need 40,000 in 6 years for a new addition. To meet the goal, the company deposits money into an account today that pays 4% annual intrest compund quarterly." Let's pretend that the instructions state, "Determine the amount of money that must be deposited upfront so that you will have $40,000 in 6 years."

Use the Compound Amount formula: A = P(1 + r/n)^(nt),
where P is the principal (the amount deposited upfront), r is the interest rate as a decimal fraction, n is the number of compounding periods, and t is the time in years.

Here, $40000 = P(1 + 0.04/4)^(4*6)
$40000
So the upfront $ needed is P =
(1+0.01)^24

This comes out to $31502.65 (answer)

Answer from: Quest

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step-by-step explanation:

Answer from: Quest

starting with:

5 + x - 12 = 2x - 7

5 + x - 12 - x = 2x - 7 - x (subtract x from both sides)

5 - 12 = x - 7 (combine and cancel x's from both sides)

5 - 12 + 7 = x - 7 + 7 (add 7 to both sides)

0 = x (add numbers together on both sides)

so in order for the equation to be true, x must be 0.

trying x = -0.5

5 + x - 12 = 2x - 7 (original equation)

5 + -0.5 - 12 = 2(-0.5) - 7 (plug in value of x)

5 + -0.5 - 12 = -1 - 7 (did multiplication)

-7.5 = -8 (did addition on both sides)

since -7.5 is obviously not equal to -8, the value of -0.5 for x is wrong.

trying x = 0

5 + x - 12 = 2x - 7 (original equation)

5 + 0 - 12 = 2(0) - 7 (plug in value of x)

5 + 0 - 12 = 0 - 7 (did multiplication)

-7 = -7 (did addition on both sides)

since -7 equals -7, that demonstrates that the value of 0 for x is correct.

trying x = 1

5 + x - 12 = 2x - 7 (original equation)

5 + 1 - 12 = 2(1) - 7 (plug in value of x)

5 + 1 - 12 = 2 - 7 (did multiplication)

-6 = -5 (did addition on both sides)

since -6 is obviously not equal to -5, the value of 1 for x is wrong.

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