The function f(x) = 4500(0.98)^x represents the value in dollars of a vehicle x years after it has been purchased new. what is the average rate of change in value per year between years 5 and 10? a. −$3676.83/year b. −$0.98/year c. −$78.16/year d. −$4500/year

C. -$78.16/year

Another average rate of change. Just calculate the function for x = 5 and x=10. Then divide the difference between those two values by the difference in x, which is 5. So

4500(0.98)^5 = 4067.64
4500(0.98)^10 = 3676.83

(3676.83 - 4067.64)/5 = -390.81/5 =  -78.16

And that value matches option "C".

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