Arectangular school banner has a length of 48 inches and a width of 30 inches. a sign is made that is similar to the school banner and has a length of 15 inches. what is the ratio of the area of the school banner to the area of the sign?

The ratio of length to width is:

ratio = 48 inches / 30 inches = 1.6

This ratio must be similar to that of the other school banner, therefore the width of that is:

width = 15 / 1.6 = 9.375 inches

The areas are:

A1 = 48 inches * 30 inches = 1440 square inches

A2 = 15 inches * 9.375 inches = 140.625 square inches

So the ratio of the area is:

A1 / A2 = 1440 / 140.625

A1 / A2 = 10.24

step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v