Snowy's snow cones has a special bubble gum snow cone on sale. the cone is a regular snow cone that has a spherical piece of bubble gum nested at the bottom of the cone. the radius of the snow cone is 4 inches, and the height of the cone is 6 inches. if the diameter of the bubble gum is 0.8 inches, which of the following can be used to calculate the volume of the cone that can be filled with flavored ice? 1 over 3(3.14)(62)(4) − 4 over 3(3.14)(0.43) 1 over 3(3.14)(42)(6) − 4 over 3(3.14)(0.43) 1 over 3(3.14)(62)(4) − 4 over 3(3.14)(0.83) 1 over 3(3.14)(42)(6) − 4 over 3(3.14)(0.83)

The volume of a cone is given by the formula: v = (1/3) (area of the base) (height)area of the base = π (radius)^2 = π(4 in)^2 = 16π in^2height = 6 in=> v = (1/3) (π) (4^2)(6) in^3now you have to substract the volume of the gum. the gum is a sphere. the gum of a sphere is: v = (4/3)π(radius)^3 radius = diameter / 2 = 0.8 in / 2 = 0.4 inv = (4/3) π (0.4)^3 in^3therefore the subtraction is: (1/3)π(4^2)(6) in^3 - (4/3)π(0.4)^3 in^3 replacing 3.14 for π: (1/3) (3.14) (4^2)(6) in^3 - (4/3)(3.14)(0.4)^3 in^3that is the second option of your list,except because you forgot to insert the symbol ^ between the number 4 and the number 2, and so it appears to be 42 instead of 4^2.the right answer is with 4^2.final answer: (1/3) (3.14) (4^2)(6) in^3 - (4/3)(3.14)(0.4)^3 in^3

200 miles.45 x 3 (charge per day times days)135$205$ - 135$ = 70$0.35x = 70divide both sides by 0.35200