Sergio has two similar cylindrical pots, pot a and pot b. the radius of pot a is 12 inches and the radius of pot b is 3 inches. what is the ratio of the volume of pot a to the volume of pot b

Pot A volume: 12 ^3 = 1728

Pot B Volume: 3^3 = 27

1728 /27 = 64

 ratio should be 64:1

64 to 1

Step-by-step explanation:

First we find the ratio of the radius of pot A to the radius of pot B:

12/3 = 4/1

A radius is a one-dimensional measurement.  Volume is a three-dimensional measurement; this means the ratio of the volumes would be the ratio of the radii cubed:

(4/1)³ = 4³/1³ = 64/1

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

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