Will give brainliest award for best show all work cause i don't get how to do this what is the solution of the linear-quadratic system of equations? {y=x^2+5x-3 {y-x=2

Substitute y. 

x^2+5x-3-x=2 

Add common factors. 

x^2+4x-3=2 

Subtract 2 from both sides of the equation. 

x^2+4x-5=0 

Quadratic Formula: 

[-4±√4²-(4*1*-5)]/(2*1)=0 
[-4±√16-(-20)]/2=0 
[-4±√36]/2=0 
[-4±6]/2=0 

(-4+6)/2 
2/2 
x=1 

(-4-6)/2 
-10/2 
x=-5 

 
x=1 
or 
x=-5 
 

2x^2-16x+32=0 

Quadratic Formula: 
(-b±√b²-4ac)/2a=0 

[16±√-16²-(4*2*32)]/(2*2)=0 
[16±√256-(256)]/4=0 
[16±√0]/4=0 
[16±0]/4=0 

(16+0)/4 
16/4 
x=4 

(16-0)/4 
16/4 
x=4 

 
x=4

It is going to be the third choice