Hurry! which absolute value function, when graphed, will be narrower than the graph of the parent function, f(x) = |x|? f(x) = |x| – 3 f(x) = |x + 2| f(x) = 0.5|x| f(x) = 4|x|

f(x) = 4|x|

Step-by-step explanation:

The fourth function, f(x) = 4|x| will have a graph narrower than that of |x|.

Hello there!

the parent function is f(x) = IxI

now let's analyze the options:

a) f(x) = IxI - 3

this is a displacement of -3 units in the y-axis, so this is not narrower than the parent function

b) f(x) = I x +2I  

this is a displacement of -2 units in the x-axis

c)f(x) = 0.5IxI

This means that the value of Y is 0.5 the value of the parent function, this means that when the parent function is 1, this function is equal to 0.5, then this graph will be wider than the one of the parent function.

d)f(x) = 4IxI

now this function increases faster than the parent function when the parent function is equal to 1, this function is equal to 4, so this function is narrower than the parent function.

So the right option is f(x) = 4IxI

step-by-step explanation:

b. 6

step-by-step explanation:

we are given the table representing an exponential function.

we can see from the table that, as x is increasing, the value of y is increasing in the power of 6.

i.e. the following relation is obtained,

x = 1, y = 6

x = 2, y = 36 =

x = 3, y = 216 =

x = 4, y = 1296 =

x = 5, y = 7776 =

so, the geometric series obtained is .

thus, the common ratio is given by = = 6.

hence, the common ratio is 6.