How many numbers greater than 3,000,000 can be formed from permutations of 1, 2, 2, 4, 6, 6, 6?

Let's look at the problem; 

There are 7 digits in 3,000,000 and 7 given digits. However, the numbers starting with either 6 or 4 will be greater than 3,000,000. 

If the first digit is 4, 6!/(2!3!) = 60 <--- I knew that there would be 3 repetitions of 6 and 2 repetitions of 2, which I divided away. 

If the first digit is 6, 6!/(2!2!)= 180 <-- repeat as above 

The first digit can be 6 or 4, therefore, we add the possible ways. 

60+180=240 possible permutations 

Hope I helped :) 

It’s 24.6 after you round to the nearest tenths the answer should be 25.0

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