Start at 5. create a pattern that multiplies each number by 3 and subtracts 2. stop when you have 5 numbers.

The required pattern is 13, 37, 109, 325, 973

Step-by-step explanation:

Since, each number in the sequence follows the following rule,

2 less than the 3 times of the previous number.

If we start from 5,

Then first number of the sequence = 3×5 - 2 = 15 - 2 = 13

Second number = 3× 13 - 2 = 39 - 2 = 37

Third number = 3× 37 - 2 = 111 - 2 = 109

Fourth number = 3×109 - 2 = 327 - 2 = 325

Fifth number = 3× 325 - 2 = 975 - 2 = 973

Hence, The required sequence is,

13, 37, 109, 325, 973

susie has 7 apples

answer: solve 5\cdot 2^x=2405⋅2  

x

=2405, dot, 2, start superscript, x, end superscript, equals, 240.

solution

to solve for xxx, we must first isolate the exponential part. to do this, divide both sides by 555 as shown below. we do not multiply the 555 and the 222 as this goes against the order of operations!

\begin{aligned} 5\cdot 2^x& =240 2^x& =48 \\ \end{aligned}  

5⋅2  

x

2  

x

​    

=240

=48

​

step-by-step explanation: