Two cargo trains each leave their respective stations at 1: 00 p. m. and approach each other, one traveling west at 6 miles per hour and the other on separate tracks traveling east at 14 miles per hour. the stations are 40 miles apart. find the time when the trains meet and determine how far the eastbound train has traveled. a). 3 p. m, 28 mi b). 12 p. m., 20 mi c). 2 p. m., 18 mi. d). 1 p. m., 15 mi

The eastbound train has traveled 28 miles and they met at 3:00 pm

Speed is the ratio of total distance to total time taken. It is given by:

Speed = distance / time

Let both cargo trains meet each other at time t.

For the train traveling west:

6 = d₁ / t

d₁ = 6t

For the train traveling east:

14 = d₂ / t

d₂ = 14t

Since both trains are 40 miles apart, hence:

d₁ + d₂ = 40

6t + 14t = 40

20t = 40

t = 2 hours

t = 3:00 pm (1:00 pm + 2 hours)

Distance travel by east bound train = d₂ = 14t = 14(2) = 28 miles

The eastbound train has traveled 28 miles and they met at 3:00 pm

Find out more on speed at: link

let x = hours

6x + 14x = 40

20x=40

x = 40/20 = 2 hours

1 pm + 2 hours = 3 pm

eastbound trains is going 14 miles per hour, 14 mph x 2 hours = 28 miles

 Answer is A. 3 pm and 28 miles

15

step-by-step explanation:

we are given the following expression and we are to solve it and find the product:

-13 × (-5)

solving the given expression in the standard order of solving a mathematical expression, beginning with the opening of brackets and then multiplying the terms and changing their signs.

-3 × -5 = 15 (answer is positive because when negative is multiplied with negative, it gives a positive answer)