Amessage center receives calls from 6 p. m. until 6 a. m. typically, 50% of the calls come in between 6 p. m. and 9 p. m.; 25% of the calls come in between 9 p. m. and midnight; 20% of the calls come in between midnight and 3 a. m.; and 5% of the calls come in between 3 a. m. and 6 a. m. what is the probability that a call will come in between 6 p. m. and midnight? question 5 options: 25% 50% 55% 75%

hi there!

the answer will be d: 2

d. 24+-0.114

step-by-step explanation:

the question requires us to calculate the approximate 95% confidence interval for the mean number of ounces of ketchup per bottle in the sample given the following statistics;

sample mean = 24

standard deviation, σ = 0.4

sample size , n = 49

the confidence interval for a population mean is calculated using the formula;

sample mean ± z-score*(σ/sqrt(n))

the z-score associated with a 95% confidence interval, from the standard normal tables, is;

1.96

substituting these values into the formula;

24 ± 1.96*(0.4/7)

= 24 ± 0.112

from the alternatives given, choice d is closest to the above expression;