Hello send the details for the area of each shape. sincerely, leanoriaia

This type of problems are solved by partitioning the figure into rectangles, whose areas we can find easily.

Picture 1)

From the point denoted by E, draw two altitudes towards the sides AG and AC.

Since ED is 3, then BC is 3. Thus, AB=4-3=1. 

Since EF is 1, then HG is 1, so AH=3-1=2.

The area of the figure is equal to the area of rectangle ACDH + the area of the square HEFG.

That is, the area of the figure is 4*2+1*1=8+1=9 (square in).

Picture 2)

As in the first part, draw the altitudes EB and EH from point E.

GF is 5, so AB is 5. This means that BC=7-5=2 (in).

FE is 3, so GH is 3, that is HA=6-3=3.

Thus, Area(figure)=Area(ABFG)+Area(BCDE)=5*6+2*3=30+6=36 (square in.)

9 (square in); 36 (square in.)

Do the math. she originally had 50 dollars on her gift card and she had 12 dollars left on her gift card after she finished her shopping spree. if you subtract 50 minus 12 you get thirty eight dollars as your answer. so therefore, ciara spent 38 dollars total o