Find two consecutive integers whose sum is 45

The two consecutive integers are:  22, and 23 .

 x + (x + 1) = 45 ;

in which:
           "x" is the first integer (of the 2 consecutive integers) ;
           "(x + 1)" is the second integer (of the 2 consecutive integers);

We want to solve for "x";
            which is the first integer (of the 2 consecutive integers);
then we can solve for the second integer (of the 2 consecutive integers);
                                                                        as well;

We have:  

     x + (x + 1) = 45 ;

Rewrite as:

     x + x + 1 = 45 ;

↔  1x + 1x + 1 = 45 ;

→  2x + 1 = 45 ;

Subtract "1" from each side of the equation;

      2x + 1 −1  = 45 − 1 ;

to get:
      2x = 44 ;

Divide EACH SIDE of the equation by "2" ; to isolate "x" on one side of the equation; and to solve for "x" ;

      2x / 2 = 44 / 2  ; 

to get:   x = 22 ;

Our two consecutive integers:

x = 22 ;

(x + 1) = 22 + 1 = 23 .

The two consecutive integers are:  "22" and "23" .

Let us check our

Are "22" and "23" consecutive integers?  Yes!

Do "22" and "23" add up to "45" ?  ; 

→ 22 + 23 = ? 45 ? ;   Yes!