"i am 3 times as old as sue is," frank said to ann. "on the other hand, i am 15 years older than john while sue is 1 year younger than john. how old am i? "

if j represents john's age, then which of the following equations could be used to solve the problem?

a. 3(j + 15) = j - 1
b. j + 15 = 3j - 1
c. j + 15 = 3(j - 1)

Frank = F

Sue = S

John = J

F=3*S

F = J+15

S = J-1

If you want to find Frank's age, then his age would be equivalent to John's plus 15 years.

A.-Would not work because Frank is three times Sue's age, not John's (left hand side of the equation).

B.-Notice that the right hand side of the equation is equivalent to Sue's age, which we know is John-1, however it is currently written to be "three times Sue's age minus one" which would give us John's age, plus two more years than his actual age on the left hand side.

C.-Frank's age is equal to John's plus fifteen (right side of the equation) and Frank is equal to Sue's age times 3. But, if Sue is in terms of Johns, then Sue's age is John's minus one. Therefore, Frank's age is equal to three times Sue's age of John minus one, which is the left-hand side of our equation.

Therefore C is the answer. C:

there is nothing below so i cannot

step-by-step explanation:

i only know the sequence of arithmetic it adds the first is 5+4 then it goes up as it adds to then it is 9+5 then 14+6 then to 20+7 and so on. 5,9,14,20,27,35.

step-by-step explanation: