Three friends were born in consecutive years. the some of their birth years is 5982.find the year in which each person was born

The birth years of first person is 1993.

The birth years of second person is 1994.

The birth years of third person is 1995.

Step-by-step explanation:

Three friends were born in consecutive years

Let the birth years of first person be  x,

Let the birth years of second person be (x+1)

Let the birth years of third person be(x+2)

The sum of their birth years is 5982.

Solving the given equation for x:

The birth years of first person = x =  1993

The birth years of second person = (x+1) = 1993+ 1 = 1994

The birth years of third person = (x+2) = 1993+2 = 1995

amount of oatypop that contains the prize = 40%

amount   of oatypop which doesn't contain the prize = (100-40)=60%

probability that hannah will win a prize

    = s +f s +f f s+ff   f s+ff f f s+ infinity.where f= failure,s= success

=   or 60%

probability that hannah only has to buy 3 or less boxes before getting a prize= (s) and ( f s) and (ff s) and (f f f s)

        = = 87.04 %  

step-by-step explanation: