Given: △ABC with a2 + b2 = c2 and right △DEF constructed with legs a and b and hypotenuse n
Prove: △ABC is a right triangle.
Complete the missing parts of the paragraph proof.
Proof:
We are given a2 + b2 = c2 for △ABC and right
△DEF constructed with legs a and b and hypotenuse n. Since △DEF is a right triangle, we know that a2 + b2 = n2 because of the
. By substitution, c2 = n2 Using the square root property and the principle root, we can take the square root of both sides to get
c = n. By
, triangles ABC and DEF are congruent. Since it is given that
∠F is a right angle, then ∠ is also a right angle by CPCTC. Therefore, △ABC is a right triangle by

spinning a 1, 2, or 3. option d.

step-by-step explanation: when spinning a number graph up to 4, and aiming for any number less than 3, that automatically eliminates the number 4. now you have two numbers to spin on that are less than 3, but the number 3 is included in this question because it's no greater of an number than itself. i hope this you : )

1/4 because there is 4 grades.

chiken

step-by-step explanation:

step-by-step explanation:

we have

using a graphing tool

see the attached figure

this is a quadratic equation (vertical parabola) open up

the vertex is a > vertex

the domain of the function is all real > interval (-∞,∞)

the range of the function is the > [-6.125,∞)

the function has two x->   and

the function is increasing over the > (0.25,∞)

the function is decreasing over the > (-∞,0.25)