What is the completely factored form of f(x)=x3+5x2+4x−6? f(x)=(x−3)(x−(−1+i3√−(−1−i3√)) f(x)=(x+3)(x−(−1+i3√−(−1−i3√)) f(x)=(x+3)(x−(−1+3√−(−1−3√)) f(x)=(x−3)(x−(−1+3√−(−1−3√))

The factored type is the product of constants and two-dimensional terms, that is the root of a function as well as the graph's x-intercepts, and the further calculation can be defined as follows:

Given:

To find:

factored form=?

Solution:

putting the value x=-1,-2,-3...... to find the function value 0.

Therefore, is the factor of the function.

Let divide by the function:

compare the value by the standard equation so,

Putting value into the quadratic equation formula:

Adding the factor value that is so, the value is ""

So, the final answer is ""

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