Solve the system by substitution 2x-y+z=-4 z=5 -2x+3y-z=10

Substituting for z in equations 1 and 3 we have

2x - y + 5 = -4
-2x + 3y - 5 = 10 

2x -  y =  -9
-2x + 3y = 15    Adding these 2 equations:-

2y = 6
y = 3 

Plugging in  y = 3 and z = 5 into the original equation:-

2x - 3 + 5 = -4

2x = -6
x = -3

so answer is x= -3,y = 3  and z = 5.

The first digit is in the middle school 100s place