The ordered pair (2 36) is a solution to which equation(s) a. y=2x^2 b. y=(3x)^2 c. y=7x^2+2 d. y=(x+4)^2

(2, 36) → x = 2, y = 36

Substitute the value of x and y to the equations of the functions:

A. y = 2x^2

36 = 2(2)^2 → 36 = 8 FALSE

B. y = (3x)^2

36 = (3 · 2)^2 → 36 = 6^2 → 36 = 36 CORRECT

C. y = 7x^2 + 2

36 = 7(2)^2 + 2 → 36 = 7 · 4 + 2 → 36 = 30 FALSE

D. y = (x + 4)^2

36 = (2 + 4)^2 → 36 = 6^2 → 36 = 36 CORRECT

B. y = (3x)^2 and D. (x + 4)^2

the figures below are made out of circles, semicircles, quarter … find the area and the perimeter of each figure and give your answers as a completely simplified exact value in terms of π (no approximations). remember that we'll also have to cut whatever areas we get in half, since we're only dealing

step-by-step explanation: