Write the expression(4x-2)·6(2x 7) in the standard form of a quadratic expression, ax² bx c what are the values of the couiffeciant?

I have found that the right expression is (4x-2)*6(2x-7).

So, I will apply distributive property step by step:

1) (4x - 2) (12x - 35)

2) 4*12x^2 - 4*35x - 2*12x + 2*35 = 48x^2 - 140x - 24x + 70 = 48x^2 - 164x + 70

3) Compare with ax^2 + bx + c

=> a = 48, b = - 164, c = 70

a = 48, b = -164, c = 70