There are two containers of milk. there is twice as much milk in the first container as in the second. after using 2 gal. of milk from the second container and 3 gal. of milk from the first container, the second container had 4.5 times less milk than the first. how many gallons of milk were in both containers originally?

Let us say that:

V1 = initial gallons in first container

V2 = initial gallons in second container

From the problem statement, we can create the equations:

V1 = 2 V2

V1 – 3 = 4.5 (V2 – 2)

Combining the two:

2 V2 – 3 = 4.5 (V2 – 2)

2 V2 – 3 = 4.5 V2 – 9

2.5 V2 = 6

V2 = 2.4 gallons

V1 = 2 V2 = 4.8 gallons

So there are 4.8 gallons in the 1st container while 2.4 gallons in the 2nd container.

the answer is d

the answer is in the first quadrant, which make the y-int positive.

since the dots are going down, therefore the correlation is negative

i hope it is right.

b. 6

step-by-step explanation:

we are given the table representing an exponential function.

we can see from the table that, as x is increasing, the value of y is increasing in the power of 6.

i.e. the following relation is obtained,

x = 1, y = 6

x = 2, y = 36 =

x = 3, y = 216 =

x = 4, y = 1296 =

x = 5, y = 7776 =

so, the geometric series obtained is .

thus, the common ratio is given by = = 6.

hence, the common ratio is 6.