Find the resultant of these two vectors: 2.00 x 102 units due east and 4.00 x 102 units 30.0° north of west.

If two vectors are represented both in magnitude and direction by the two adjacent sides of a triangle taken in an order, then their resultant is given by the third side taken in the reverse order.

Resultant vector :

                          R = sqrt of A^2 + B^2 + 2ABcosθ

given :

           A = 200 units

           B = 300 units

           θ = 30 degrees

∴ R = sqrt of 200^2 + 300^2 + 2(200)(300)cos35

the answer is 477.805656

the answer to the expression is 83

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