The anova from a randomized complete block experiment output is shown below. source df ss ms f p treatment 4 1010.56 ? 29.84 ? block ? ? 64.765 ? ? error 20 169.33 ? total 29 1503.71 (a) fill in the blanks. you may give bounds on the p-value. (b) how many blocks were used in this experiment? (c) what conclusions can you draw?

Source        DF     SS           MS         F          PTreatment   4       1010.56    252.64   29.84   3.545E-08Block           5       323.825   64.765   7.649    0.00037Error           20     169.33      8.467 Total           29     1503.71

d.f. for blocks =b-1= 29-(20+4)= 29-24=5Hence here b=6 blocks were used. MS for treatment  Ms for error =  So SS for Blocks = MS * df =64.765*5 = 323.825F for block =  p value for treatment using excel : 'fdist(29.84,4,20)' = 3.545E-08p value for block : 'fdist(7.649,5,20)' = 0.00037Here p value for treatment ( 0.0000000354) <   ( 0.05 )Hence we reject null hypothesis.Also p value for block (0.00037 ) <   ( 0.05 )Hence we reject null hypothesisConclusion : There is difference between treatment means as well as block means.

Hello!

the answer is:

the answer is:

why?

to solve the problem, we need to remember the quotient of power property, it's defined by the following relation:

if we have a quotienf of powers that have the same base, we need to keep the same base and subtract the exponent of the denominator power to the exponent of the numerator power.

so, we are given the expression:

then, calculating we have:

hence, the answer is:

have a nice day!