There are 9 red and 6 green marbles in a bag. a child reaches in the bag and randomly takes one marble. what is the probability pf that child getting a green marble

 The required probability that the child took a green marble is 40%.

Step-by-step explanation:  Given that there are 9 red and 6 green marbles in a bag and a child reaches in the bag and randomly takes one marble.

We are to find the probability that the child took a green marble.

Let S denote the sample space of choosing a marble from the bag and A be the event of choosing a green marble.

Then,

n(S) = 9 + 6 = 15   and   n(A) = 6.

Therefore, the probability of event A will be

Thus, the required probability that the child took a green marble is 40%.

google dat sis

step-by-step explanation:

d, x=8

step-by-step explanation:

simplifying

4x + -5 = 2x + 11

reorder the terms:

-5 + 4x = 2x + 11

reorder the terms:

-5 + 4x = 11 + 2x

solving

-5 + 4x = 11 + 2x

solving for variable 'x'.

move all terms containing x to the left, all other terms to the right.

add '-2x' to each side of the equation.

-5 + 4x + -2x = 11 + 2x + -2x

combine like terms: 4x + -2x = 2x

-5 + 2x = 11 + 2x + -2x

combine like terms: 2x + -2x = 0

-5 + 2x = 11 + 0

-5 + 2x = 11

add '5' to each side of the equation.

-5 + 5 + 2x = 11 + 5

combine like terms: -5 + 5 = 0

0 + 2x = 11 + 5

2x = 11 + 5

combine like terms: 11 + 5 = 16

2x = 16

divide each side by '2'.