Point p is reflected across two lines. point a is its reflection image. which two lines is point p reflected across? x = 3 and y = 2 x = -2 and y = 2 x = 3 and y = -3 x = -2 and y = -3

 The two lines are x = -2 and y = 2.

Step-by-step explanation:  Given that the point P on the co-ordinate plane is reflected across two lines and A is its image after the reflection.

We are to find the two lines across which the point P is reflected.

The co-ordinates of point P are (0, 0) and the co-ordinates of its image A after reflection from two lines are (-4, 4).

From the given figure, we can note that

the first line of reflection is y = 2. Point C(0, 4) is the image after reflection from first line.

The second line of reflection is x = -2. Point A(-4,4) is the final image after second reflection.

Thus, the two lines are x = -2 and y = 2.

step-by-step explanation:

in the absence of parentheses, i will have to make some assumptions:   i interpret your (3x+5/y^6)(4y^3/5)​ to mean:

3x + 5     4y^(3/5)       (3x + 5)(4)

* =

    y^6             1               y^(6-3/5)

if this is not what you expected, repost your question using parentheses to indicate whether you meant

4y^3

    or   4y^(3/5)

    5

step-by-step explanation: