In a random sample of 55 newborn babies, what is the probability that 44% or fewer of the sample are boys. (use 3 decimal places). hint: you are asked to find p(p^^\^ < .44 ). to calculate this first find the z-score and then calculate the probability

0.053 The standard deviation of a binomial variable is sqrt(n*P*(1-P)) where n is the sample size and P is the probability of one of the outcomes. The sample size is 55 and we'll assume that both male and female are equally likely outcomes. standard deviation = sqrt(55*.5*.5) = 3.7081% 44% is 1.6181 standard deviations away from the mean of 50%. Looking this up on a standard deviation chart gives .0526 probability which we'll round to 0.053

Best answer that i found on yahoo ok   set :   x= length of 2nd piece in cm  x- 3= length of 1st piece in cm  x-4= length of 3rd piece in cm  then since you know they all came from the 20 cm ribbon you add them together and set them equal to 20x+ x-3 +x-4 = 20  3x - 7= 20  3x= 27  x= 9  the shortest piece is the third piece which is x- 4  x-4  9-4 = 5  the length of the smallest piece is 5 cm.  the other lengths are  9 cm  6 cm