Aball is thrown downward from a window in a tall building. its position at time t in seconds is s = 16t^2 + 32t, where s is in feet. how long (to the nearest tenth) will it take the ball to fall 211 feet

So When S is equal to 211
S = 16t^2 + 32t
211 = 16t^2 + 32t
Then, turn into a quadratic equation
0= 16t^2 + 32t - 211

Afterwards, simply find the roots of the equation by using your calculator formula 01.
you will be getting two answers,
t = 2.7666 (correct to 3 significant figures)
t = -4.7666...(reject this because of its negative sign)

therefore, it will take 2.78 for the ball to fall 211 feet.

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2160ft^3 i think you could use a formala to you out with this in the future