What is the area of a parallelogram whose vertices are a(−1, 12) , b(13, 12) , c(2, −5) , and d(−12, −5) ?

The area of the parallelogram with the given vertices=238 square units.

Step-by-step explanation:

Let CD be the base of the parallelogram ABCD is given by distance formula

CD=units[or you can count distance by using graph as ordinates of C and D are same to we can count the distance of x from C to D]

Now consider P a point on CD such that AP become the height of the parallelogram which is given by (from the graph attached)=17 [as abscissa of P and A are same to we can count the distance of y from A to P]

Area of parallelogram = base × height=14×17=238 square units.

i think it's either c or d

step-by-step explanation: the entire question is extremely odd. 04 obviously refers to the interest rate. honestly i will say the answer is c. because the (2 x 12) part would mean it's compounded semiannually. i'll say choose c.

step-by-step explanation:

x^2 -12x + 36 + y^2 = 36

x^2 + y^2 = 12x

r^2 = 12rcos(theta)

r = 12 cos(theta)