Suppose that 16-ounce bags of chocolate chip cookies are produced with weights that follow a normal distribution with mean weight 16.1 ounces and standard deviation 0.1 ounce. for the distribution, approximately what percent of the bags will likely be underweight (that is, less than 16 ounces)?

To solve this we use the z statistic. The formula for z score is:

z = (x – u) / s

where x is the sample value = less than 16, u is the sample mean = 16.1, s is standard dev = 0.1

z = (16 – 16.1) / 0.1

z = - 1

From the standard distribution tables at z = - 1,

P (z = -1) = 0.1587

So about 15.87% is underweight.

true !

step-by-step explanation:

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet