The nth term of a sequence is n+7 . what are the first 3 terms of the sequence

First 3 terms of the sequence are:

8,9,10

Step-by-step explanation:

The nth term of a sequence is n+7 .

We have to find the first three terms of the sequence

First term(n=1)   = 1+7 =8

Second term(n=2)   = 2+7 =9

Third term(n=3)      = 3+7 =10

Hence, first 3 terms of the sequence are:

8,9,10

37/3

step-by-step explanation:

step 1: simplify both sides of the equation.

7x+8(x+

1

4

)=3(6x−9)−8

7x+(8)(x)+(8)(

1

4

)=(3)(6x)+(3)(−9)+−8(distribute)

7x+8x+2=18x+−27+−8

(7x+8x)+(2)=(18x)+(−27+−8)(combine like terms)

15x+2=18x+−35

15x+2=18x−35

tep 2: subtract 18x from both sides.

15x+2−18x=18x−35−18x

−3x+2=−35

step 3: subtract 2 from both sides.

−3x+2−2=−35−2

−3x=−37

step 4: divide both sides by -3.

−3x

−3

=

−37

−3

x=

37

3