Really need i have no idea what the answer is

 x = 7 ;  y = 4 .

sin 30 / (5y - 4) = sin 30 / (y + 12) ;

(sin 60) / (5y - 4) = (sin 60) / (3x - 5) ;

5y - 4 = 3x - 5 ; 

5y - 4 = 3x - 5  = y + 12 ;


5y - 4 = y + 12 ; solve for "y" ;

Add "4" to each side of the equation; & Subtract "5y" from each side of the equation:

          5y - 4 + 4 - 5y = y + 12 + 4 - 5y ;

to get:   0 = -4y + 16 ;
   
          ↔  -4y + 16 = 0 ;

Subtract "16" from each side of the equation:

            -4y + 16 - 16 = 0 - 16 ;

  to get:  -4y = -16 ;

Now, divide EACH SIDE of the equation by "-4" ; to isolate "y" on each side of the equation; and to solve for "y" :

-4y / -4 = -16 / -4 ; 

to get:  " y = 4 " ,

Now, to solve for "x" :

 Since:
  
 5y - 4 = 3x - 5 ; 

Substitute "4" for "y" (in the equation); and solve for "x" ;

(5*4) - 4 = 3x - 5 ;

20 - 4 = 3x - 5 ;

16 = 3x - 5 ;

↔ 3x - 5 = 16 ;

Add "5" to each side of the equation;

   3x - 5 + 5 = 16 + 5 ;

   3x = 21 ;

Now divide EACH SIDE of the equation by "3" ; to isolate "x" on ONE SIDE of the equation; and to solve for "x" ; 

    3x / 3 = 21 / 3 ;

      x = 7 ; 

Let us check our work:

 Given the equation: 

"  5y - 4 = 3x - 5 " ;

→ Does the equation hold true when "x = 7" and "y = 4" ?

→ On the "left-hand side" of the equation:

"5y - 4" = 5(4) - 4 = 20 - 4 = 16 .

On the "right-hand side" of the equation:

 3x - 5 = 3(7) - 5 = 21 - 5 = 16 .

Does "16 = 16" ?  Yes! .

Also, note:  "5y - 4 = 3x - 5  = y + 12 ".  

Does: "y + 12 = 16" ;  when "y = 4" ?

  →  y + 12 = 4 + 12  = 16.  Yes!

Our values:  x = 7 , y = 4 .

If gravity is one third on mars then weight also one third on mars