Mathematics, 06.07.2019 10:20 veronicamixon1970
How do you solve cot^2x + cscx= 1 (0,2pi)
Answers: 1
![\bf 1+cot^2(\theta)=csc^2(\theta)\implies cot^2(\theta)=csc^2(\theta)-1 \\\\\\ csc(\theta)=\cfrac{1}{sin(\theta)} \\\\ -------------------------------\\\\ cot^2(x)+csc(x)=1\implies csc^2(x)-1+csc(x)=1 \\\\\\ csc^2(x)+csc(x)-2=0\implies [csc(x)-2][csc(x)+1]=0\\\\ -------------------------------\\\\](/tpl/images/0057/5376/a63c3.png)
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