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Mathematics, 06.07.2019 05:00 gabriellarenolp5x7c0

Ihave the problem solved but i dont know how they got it. an equation for the line tangent to y= -5-9x^2 at (2,-41). i use limh→0 f( x0+h)-f(x0)/h to get the slope of tan line which is -36, then it says i need to get the slope-intercept form with the equation below and i'm not sure how -36= )/)

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Ihave the problem solved but i dont know how they got it. an equation for the line tangent to y= -5-...
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