Solve the equation 2a+b=2a, where a and b are nonzero, real numbers. describe the solution to this equation and justify your description.

To solve this equation we can first assume that both a and b are nonzero real numbers. Hence, A = 1 b = 1
1.   2 (1) + 1 = 2(1)
2.    2 + 1 = 2: now this a false equation since there is not equality, the equation cannot retain the equal sign but will become 2 + 1 > 2. Leaving the relationship unequal.

However, the alternative to this problem is to be b = 0. To oversee the rule in order to solve the equation retaining it as an “equation”. Further, there is no other solution for this equation. A = 1 b = 0
1.   Which becomes 2(1) + 0 = 2(1)
2.    2 + 0 = 2 :
3.    2 = 2. Here we can observe the equality.

The answer is 10. and if you go by pemdas you would 1. multiplication 2. division 3. addition 4. subtraction