1. what is the remainder when x^2+4 is divided by x-2? 2. evaluate f(-1) using substitution: f(x)=2x^3-3x^2-18x-8 3. the point (1,0) lies on the graph of p(x)=x^4-2x^3-x+2 true or false 4. if x-1 is a factor of p(x)=x^3-7x^2+15x-9, which of the following represents the complete factorization for p(x)? a. (x-3)(x+4)(x+1) b. (x-3)(x-3)(x-1) c. (x-3)(x+3)(x-1) d. (x-3)(x+3)(x+1)

1) 8

2) 5

3) False

4) Option B

Step-by-step explanation:

1) We have to find the remainder when we divide (x² + 4) by (x - 2)

To get the remainder we will put x = 2 in (x² + 4)

= (2)² + 4

= 8

2). We have to evaluate f(-1) using substitution in f(x) = 2x³ - 3x² - 18x - 8

f(-1) = 2(-1)³ - 3(-1)²- 18(-1) - 8

      = 2(-1) - 3 + 18 -8

      = -2 - 3 + 18 - 8

      = 5

3) The point (1, 0) lies on the graph of p(x) =

If this point lies on the graph then p(1) should be equal to zero.

p(1) = 1³ - 7(1)² + 7(1) - 9

     = 1 - 7 + 7 - 9

     = -8 ≠ 0

Therefore, It's false.

4). (x - 1) is a factor of p(x) = x³ - 7x² + 15x - 9

Now we will factorize it further when (x - 1) is a zero factor.

By Synthetic division

1 |  1    - 7     15    -9

           1      -6     9

-----------------------------

    1     -6      9     0

Now we have got the expression as (x - 1)(x²- 6x + 9)

Or (x -1)(x² - 6x + 9) = (x - 1)(x - 3)(x - 3)

Therefore, Option B. is the answer.

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step-by-step explanation:

7.   there are 10 data points in the set.   the middle point is between 5 and 6.   the middle point in the top half is 8   and the middle point in the bottom half is 3. to find the iqr , take point 8 and subtract point 3

mid term   point 8 = 100   point 3 = 88

iqr = 100-88 = 12

final   point 8 = 93   point 3 = 78

iqr = 93 - 78 = 15

the final has the greatest iqr

6.   b - there is a high data value that causes the data set to be asymmetrical for the males: the data for males are high and asymmetrical .   there is an outlier for the males that skews the data

5.   the   iqr is a better measure of spread for the movies and basketball games.   since the basketball game has an outlier, we do not want to use standard deviation for measurement.  

3.   the exam median is much higher than the class median.   the median line is farther to the right on the exams

2.   there is no way to tell what the means are from the box and whisker plots.  

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step-by-step explanation:

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