The coordinates of the vertices of △abc are a(−4, 6) , b(−2, 2) , and c(−6, 2) . the coordinates of the vertices of △a′b′c′ are a′(2, 6) , b′(0, 2) , and c′(4, 2) . drag and drop the answers into the boxes to correctly complete the statement. a sequence of transformations that maps △abc to △a′b′c′ is a blank followed by a blank. translation 2 units left reflection across the x-axis reflection across the y-axis translation 2 units down

Answer-

The sequences of transformations that maps △ABC to △A′B′C′ are

Solution-

The coordinates of the vertices of ΔABC are

A = (−4, 6)

B = (−2, 2)

C = (−6, 2)

The coordinates of the vertices of ΔA′B′C′ are

A′ = (2, 6)

B′ = (0, 2)

C′ = (4, 2)

As all the y-coordinates of all the function are same, so the triangle is neither translated up or down (∵ (x, y) → (x, y±k)), nor reflected over x-axis(∵ (x, y) → (x, -y)).

As the signs of x-coordinate is changed, it might be reflected over y axis,

Rule for reflection over y axis is,

(x, y) → (-x, y)

so,

A" = (4, 6)

B" = (2, 2)

C" = (6, 2)

As the x-coordinates of vertices of ΔA′B′C′ are 2 units less than that of ΔA"B"C"

So it is then translated 2 units left.

Therefore, the sequences of transformations that maps △ABC to △A′B′C′ are

Here is my test answer

Step-by-step explanation:

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step-by-step explanation:

just for that im not answering

the graph in the attached figure

step-by-step explanation:

we have

using a graphing tool

the graph in the attached figure

the roots are ( x-intercepts) x=-0.5,x=1,x=3

the y-intercept is the point (0,3)