An important part of customer service responsibilities of a cable company relates to the speed with which trouble in service can be repaired. historically, the data show that the likelihood is 0.75 that troubles in a residential service can be repaired on the same day. for the first 5 troubles reported on a given day, what is the probability that fewer than 2 troubles will be repaired on the same day?

The probability that fewer than 2 troubles will be repaired on the same day is:

0.015576

Step-by-step explanation:

We have to use the Binomial function is n=order to calculate the probability of r successes out of the n-events.

We know that the probability of r success out of the n-events is given by:

where p is the probability of an success.

Here we have:

n=5 and r=0,1.

since we are asked to find the probability that fewer than 2 troubles will be repaired on the same day.

i.e we have to find:

Also p=0.75 ( since, likelihood is 0.75 that troubles in a residential service can be repaired on the same day )

Hence,

and

Hence,

Hence,  the probability that fewer than 2 troubles will be repaired on the same day is:

0.015576

the terms of a geometric sequence can be found by beginning with the first term and multiplying by the common ratio repeatedly. a recursive formula for a geometric sequence with common ratio r is given by an=ran−1 a n = r a n − 1 for n≥2 n ≥ 2 .

step-by-step explanation:

answer: 1inch=7days  

12inch=12*7=84days

step-by-step explanation: