Mathematics, 28.08.2019 07:00 MartinTDL
How do i find a2 and a3 for the following geometric sequence? 54, a2, a3, 128
Answers: 2
![54, a_2, a_3, 128 \\ \\ a_1=54 \\ a_4=128 \\ \\ a_n=a_1 \times r^{n-1} \\ a_4=a_1 \times r^3 \\ 128=54 \times r^3 \\ \frac{128}{54}=r^3 \\ \frac{128 \div 2}{54 \div 2}=r^3 \\ \frac{64}{27}=r^3 \\ \sqrt[3]{\frac{64}{27}}=\sqrt[3]{r^3} \\ \frac{\sqrt[3]{64}}{\sqrt[3]{27}}=r \\ r=\frac{4}{3}](/tpl/images/0204/9309/d8e4b.png)
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How do i find a2 and a3 for the following geometric sequence? 54, a2, a3, 128...
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