What is the value of x. in circle a bae = dae

x = 17 is the answer.

Step-by-step explanation:

In the given question ΔABE and ΔADE have been given where ∠BAE ≅ ∠EAD (central angles formed by chords BE and ED) and AB = AE = AD (Radii of the circle)

We have to find the value of x.

Since ∠BAE ≅ ∠EAD and AB = AE = AD are completing the property (SAS) of the congruence of two triangles Δ BAE ≅ ΔEAD

Therefore BE/ED = AB/AD

(3x-24)/(x + 10) = r/r = 1/1

(3x - 24) = (x + 10)

3x - x = 24 + 10

2x = 34

x = 34/2 = 17

Answer is x = 17

coin flip

non-answer:

choosing

sorry if this isnt what you're looking for i dont really understand the question

the polynomial is a perfect square trinomial of the form a^2-2ab+b^2:

option a. true

step-by-step explanation:

9x^2-12x+4

comparing with the form a^2-2ab+b^2

1.) a^2=9x^2

solving for a: square root both sides of the equation:

sqrt(a^2)=sqrt(9x^2)

a=sqrt(9) sqrt(x^2)

a=3x

2.) b^2=4

solving for b: square root both sides of the equation:

sqrt(b^2)=sqrt(4)

b=2

to be a perfet square trinomial 2ab must be equal to 12x. let's check:

2ab = 2 (3x) (2)

2ab = 12x

correct