Ihave a bag of 9 ordinary coins and 1 double headed one. i remove a coin and flip it three times. it comes up heads every time. what's the probability that i picked the double-headed coin?

8/17 If you pick an ordinary coin and flip it 3 times, coming up heads each time, that's a probability of 1/10 * 1/2 * 1/2 * 1/2 = 1/80. Since you have 9 such coins the probability of doing so with a ordinary coin is 9/80. Finally, you have a 1/10 chance of picking up the double headed coin, so the probability of coming up with all heads on that coin is 1/10. So you now have 2 probabilities for seeing 3 heads in a row. 9/80 and 1/10. Since you do see 3 heads in a row, those two probabilities have to add up to 100%. So let's see what percentage of the sum each probability comes to. Total = 9/80 + 1/10 = 9/80 + 8/80 = 17/80 Ordinary coin = 9/80 / 17/80 = 9/80 * 80/17 = 9/17 Double headed coin = 8/80 / 17/80 = 8/80 * 80/17 = 8/17 The probability of having picked up the double headed coin and observing 3 heads in a row is 8/17

I’ve taken this before. the answer is c

first anwser choice.

step-by-step explanation:

the greater/less or equal to symbol (> or < with the line at the bottom) is a closed/filled in circle.

when multiplying or dividing by a negative on both sides you have to flip the inequality sign. this rule only applies to multiplying or dividing by a negative number in inequality equations. this rule is really important.

-5c + 2 _< _27

subtract from both sides by 2

-5c _< _ 27

divide both sides by -5

c _< _ 5.4

flip the inequality sign

c _> _5.4

the only possible answer that would match the simplified inequality is the first answer choice