If y=3x+ 2 were changed to y=3x+8 how would the graph of the new function compare with the first one? a) it would be shifted down b) it would be shifted right c) it would be steeper d) it would be shifted up

logv3(x+2)=1

rewrite in exponential form:

logb(x) = y is equal to b^y =x

b = 3, y = 1

now solve for x:

3^1 = x+2)

x = 3-2

x = 1

see the picture for the graph.

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step-by-step explanation:

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