Darren wins a coupon for $4 off the lunch special for each of 5 days. he pays $75 for his 5 lunch specials. write and solve an equation to find the original price p for one lunch special

Our required equation is and $19 is the original price for one lunch special.

Step-by-step explanation:

Let the original price for one lunch special be 'p'.

Amount off for each of 5 days = $4

Number of days = 5

Amount he pays for 5 lunch specials = $75

According to question, it becomes,

So, it becomes,

So, original price for one lunch special is $19.

Hence, our required equation is and $19 is the original price for one lunch special.

The original price for one lunch meal is $19

The coupon reduces the total amount he paid per meal. Darren would pay for $4 less for his meal

Coupon per lunch = $4

Total amount he paid in 5 days = $75

Amount he pays per day for his lunch = $75/5 = $15

Original price p for his lunch = amount paid per lunch + coupon

p = $15 + $4

p = $19

A similar question was solved here: link

b

step-by-step explanation:

u take $75 minus $60.the anwer/original($75)multiply by 100

the answer is 150.6

step-by-step explanation:

you multiply .02 by 30 and get .6.

and then you multiply 5.00 by 30 and get 150.

hope this !