How do i solve for x? *you have to show work*
1.) 2e^2x + 4xe^2x = 0
2.) 2 + 3(4)^(2x-1) = 43

1) Factor the equation first:




So either or . But can never equal 0! So, we only need to solve for the second equation:




2) First, single out the term with the exponent:





Now, taking the log base 4 of each side gives us



and we can now solve for x: